Critical Points and the First Derivative Test
10 tutor-authored questions for this Ontario curriculum expectation, ordered easiest to hardest — every one with a full worked solution. Work through them free, no account needed.
Sample: the first question, solved
Find the critical point of f(x)=x²−6x+8.
📘 Worked solution
✓f'(x)=2x−6. Setting f'(x)=0 gives 2x−6=0, so x = 3.
And one from the hard end
Find the critical points of f(x)=x³−3x²−9x+5.
Solution shown after you try it in practice mode.
Work through all 10, easiest to hardest
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