Solve a linear system by substitution or elimination
Solve a system of two linear equations algebraically, using substitution when one equation isolates a variable and elimination otherwise. Unlimited questions, five difficulty levels, and a full worked solution every time — free.
Try one
Solve the system of equations.
y = −3x - 10
5x - 6y = −9
Answer: (-3, -1)
See one solved, step by step
Solve the system of equations.
−3x + y = 24
−x + y = 12
📘 Worked solution
1−3x + y = 24 and −x + y = 12This is a linear system — solve using elimination.
2The y-coefficients already match (both 1), so subtract the equations directly.No scaling needed since the y-terms already line up.
3−2x = 12Subtract the second scaled equation from the first — the y-terms cancel.
4x = 12 / −2 = −6Divide to solve for x.
5y = (24 - −3·-6) / 1 = 6Substitute x = -6 back into the first original equation and solve for y.
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