Scalar equation of a plane
Find the value of D in the scalar equation ax + by + cz = D of a plane, given a normal vector or two direction vectors. Unlimited questions, five difficulty levels, and a full worked solution every time — free.
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A plane has normal vector n = (4, 3, -6) and passes through the point P = (-5, -3, -4). Find D in the scalar equation 4x + 3y + -6z = D.
Answer: -5
See one solved, step by step
A plane has normal vector n = (4, 3, -6) and passes through the point P = (4, 0, 2). Find D in the scalar equation 4x + 3y + -6z = D.
📘 Worked solution
1D = 4(4) + 3(0) + −6(2)Since P lies on the plane, its coordinates must satisfy the scalar equation.
2= 4Evaluate the arithmetic.
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